c^2-11c+28=

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Solution for c^2-11c+28= equation:


Simplifying
c2 + -11c + 28 = 0

Reorder the terms:
28 + -11c + c2 = 0

Solving
28 + -11c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(4 + -1c)(7 + -1c) = 0

Subproblem 1

Set the factor '(4 + -1c)' equal to zero and attempt to solve: Simplifying 4 + -1c = 0 Solving 4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1c = 0 + -4 -1c = 0 + -4 Combine like terms: 0 + -4 = -4 -1c = -4 Divide each side by '-1'. c = 4 Simplifying c = 4

Subproblem 2

Set the factor '(7 + -1c)' equal to zero and attempt to solve: Simplifying 7 + -1c = 0 Solving 7 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1c = 0 + -7 -1c = 0 + -7 Combine like terms: 0 + -7 = -7 -1c = -7 Divide each side by '-1'. c = 7 Simplifying c = 7

Solution

c = {4, 7}

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